Q35

IF abc+bcd+cde+dea+eab=2664, a+b+c+d+e=?

(100a+10b+c)+(100b+10c+d)+(100c+10d+e)+(100d+10e+a)+(100e+10a+b) =2664

111a+111b+111c+111d+111e=2664

111(a+b+c+d+e)=2664

a+b+c+d+e=24