What is a three-digit positive number such that if the multiplication of its digits is multiplied by 5, result equals the number itself?
5*a*b*c= 100a+10b+c
Digit (c) should be 5( doesnt matter which number you multiply last digit is allways 5)
then 25a*b=5(20a+2b+1)
5*a*b=20a+2b+1
5*a*b=2(10a+b)+1
After trying all numbers i got abc=175
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